Question

solve for v, where v is a real number.\\(\sqrt{v + 4} = 6\\)\
if there is more than one solution, separate them with commas.\
if there is no solution, click on
o solution\.\
\\(v = \\)\
no solution, \\(\sqrt{\square}\\), \\(\sqrt\square{\square}\\), \\(\frac{\square}{\square}\\), \\(\square,\square,...\\)

Explanation:

Step1: Eliminate the outer square root

To solve for \( v \), we first square both sides of the equation \(\sqrt{v + 4}=6\) to get rid of the square root on the left side. Squaring both sides gives us \((\sqrt{v + 4})^2 = 6^2\), which simplifies to \(v + 4=36\).

Step2: Solve for \( v \)

Now, we subtract 4 from both sides of the equation \(v + 4 = 36\) to isolate \( v \). So, \(v=36 - 4\), which simplifies to \(v = 32\).

Answer:

\(32\)