Question

solve for v, where v is a real number.\\(\sqrt{v - 6} + 15 = 8\\)\
if there is more than one solution, separate them with commas.\
if there is no solution, click on
o solution\.\
\\(v = \square\\)

Explanation:

Step1: Isolate the square root term

Subtract 15 from both sides of the equation $\sqrt{v - 6}+15 = 8$.
We get $\sqrt{v - 6}=8 - 15=-7$.

Step2: Analyze the square root's range

The square root of a real number, $\sqrt{x}$, is always non - negative for real $x$ (i.e., $\sqrt{x}\geq0$ when $x\geq0$). Here, the left - hand side $\sqrt{v - 6}$ represents a square root, so $\sqrt{v - 6}\geq0$. But we have $\sqrt{v - 6}=-7$, and $-7<0$, which is a contradiction.

Answer:

No solution