Question

solve $x^2 = 31$, where $x$ is a real number. simplify your answer as much as possible. if there is more than one solution, separate them with commas. if there is no solution, click
o solution.\ your answer $x = \square$

Explanation:

Step1: Take square root of both sides

To solve the equation \(x^2 = 31\) for \(x\) (where \(x\) is a real number), we take the square root of both sides. Remember that for any real number \(a\), if \(x^2=a\), then \(x = \pm\sqrt{a}\) (when \(a\geq0\)). Here, \(a = 31\) which is greater than \(0\), so we can apply this property.

Taking the square root of both sides of \(x^2=31\), we get \(x=\pm\sqrt{31}\).

Answer:

\(-\sqrt{31}, \sqrt{31}\)