Question

1. solve for the unknown

use the relationship among displacement, velocity, and time interval to find δx₁ during δt₁ = 10.0 s.
x1 = 10v
use the same relationship to find δx₂ during δt₂ = 20.0 s.

Explanation:

Step1: Recall the formula

The formula for displacement is $\Delta x = v\Delta t$.

Step2: Find $\Delta x_1$

Given $\Delta t_1 = 10.0\ s$, using $\Delta x_1=v\Delta t_1$, we get $\Delta x_1 = 10v$.

Step3: Find $\Delta x_2$

Given $\Delta t_2 = 20.0\ s$, using $\Delta x_2=v\Delta t_2$, we substitute $\Delta t_2$ into the formula: $\Delta x_2 = 20v$.

Answer:

$\Delta x_1 = 10v$, $\Delta x_2 = 20v$