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solve the system by substitution. $y = 6x + 10$ $y = 4x$

Question

solve the system by substitution.
$y = 6x + 10$
$y = 4x$

Explanation:

Step1: Substitute \( y = 4x \) into \( y = 6x + 10 \)

Since both equations equal \( y \), we can set them equal to each other: \( 4x = 6x + 10 \)

Step2: Solve for \( x \)

Subtract \( 6x \) from both sides: \( 4x - 6x = 6x + 10 - 6x \)
Simplify: \( -2x = 10 \)
Divide both sides by -2: \( x = \frac{10}{-2} = -5 \)

Step3: Substitute \( x = -5 \) into \( y = 4x \)

\( y = 4\times(-5) = -20 \)

Answer:

The solution to the system is \( x = -5 \) and \( y = -20 \), or the ordered pair \( (-5, -20) \)