Question

solve for x and y in the special right triangle. (10) 7√2 45° x = 14 y = 14√2 x = 7, y = 7√2 x = 14√2 y = 7√2 x = 14 y = 7√2

Explanation:

Step1: Identify triangle type

It is a 45-45-90 right triangle (isosceles right triangle).

Step2: Recall side ratios

In 45-45-90 triangle, leg : leg : hypotenuse = $1:1:\sqrt{2}$.

Step3: Calculate hypotenuse (x)

Given one leg = $7\sqrt{2}$, hypotenuse $x = leg \times \sqrt{2} = 7\sqrt{2} \times \sqrt{2} = 7 \times 2 = 14$.

Step4: Determine other leg (y)

Legs are equal in 45-45-90 triangle, so $y = 7\sqrt{2}$.

Answer:

x=14 y=7√2