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solve for x. round to the nearest tenth, if necessary. triangle with ri…

Question

solve for x. round to the nearest tenth, if necessary. triangle with right angle at t, ut = 75, angle at s is 26 degrees, side us is x

Explanation:

Step1: Identify triangle type and trigonometric ratio

This is a right triangle (∠T = 90°). We know side UT = 75 (opposite to angle S = 26°) and we need to find hypotenuse x. The sine ratio is \(\sin(\theta)=\frac{\text{opposite}}{\text{hypotenuse}}\). So \(\sin(26^\circ)=\frac{75}{x}\).

Step2: Solve for x

Rearrange the formula: \(x = \frac{75}{\sin(26^\circ)}\). Calculate \(\sin(26^\circ)\approx0.4384\). Then \(x=\frac{75}{0.4384}\approx171.1\).

Answer:

171.1