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solve for x. round to the nearest tenth, if necessary. triangle with ri…

Question

solve for x. round to the nearest tenth, if necessary.
triangle with right angle at t, angle at s is 72 degrees, side ut is 9.4, side su is x

Explanation:

Step1: Identify trigonometric ratio

In right triangle \( STU \), \( \angle S = 72^\circ \), \( UT = 9.4 \) (adjacent to \( \angle S \)), and \( SU = x \) (hypotenuse). We use cosine: \( \cos(72^\circ)=\frac{\text{adjacent}}{\text{hypotenuse}}=\frac{UT}{SU} \).

Step2: Substitute values

\( \cos(72^\circ)=\frac{9.4}{x} \), solve for \( x \): \( x = \frac{9.4}{\cos(72^\circ)} \).

Step3: Calculate \( \cos(72^\circ) \)

\( \cos(72^\circ)\approx0.3090 \).

Step4: Compute \( x \)

\( x=\frac{9.4}{0.3090}\approx30.4 \).

Answer:

\( 30.4 \)