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solve for x. round to the nearest tenth, if necessary. answer attempt 1…

Question

solve for x. round to the nearest tenth, if necessary.
answer attempt 1 out of 3
x =
submit answer

Explanation:

Step1: Identify triangle type

The triangle has a right angle, so it's right-angled.

Step2: Apply Pythagorean theorem

Let the legs be 21 and 20, hypotenuse $x$.
$$x^2 = 21^2 + 20^2$$

Step3: Calculate squares

$$21^2 = 441, 20^2 = 400$$

Step4: Sum the squares

$$x^2 = 441 + 400 = 841$$

Step5: Find square root

$$x = \sqrt{841} = 29$$

Step6: Round to nearest integer

29 is already integer, so $x=29$ (Note: Correction—original legs might be 20 and 21, hypotenuse 29; typo in initial leg assumption fixed)

Wait, correction: The right triangle legs are 20 and 21, hypotenuse is 29. So final answer is 29.

Step1: Recognize right triangle

Triangle has a right angle.

Step2: Apply Pythagoras' theorem

$$x^2 = 20^2 + 21^2$$

Step3: Compute squares

$$20^2=400, 21^2=441$$

Step4: Sum values

$$x^2=400+441=841$$

Step5: Take square root

$$x=\sqrt{841}=29$$

Answer:

3