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9. solve for x (with a right triangle diagram, one leg is \\(\\sqrt{7}\…

Question

  1. solve for x (with a right triangle diagram, one leg is \\(\sqrt{7}\\), the other leg is x, and the triangle is isosceles as indicated by the marks)

Explanation:

Step1: Identify Triangle Type

The triangle is right - angled (has a right - angle symbol) and two sides are marked as equal (the tick marks), so it's an isosceles right - triangle. In an isosceles right - triangle, the two legs are equal in length.

Step2: Determine the Value of \(x\)

One leg has a length of \(\sqrt{7}\), and since the triangle is isosceles right - angled, the other leg (which is \(x\)) should be equal to the length of the given leg. So \(x=\sqrt{7}\).

Answer:

\(x = \sqrt{7}\)