QUESTION IMAGE
Question
- solve for b. y = mx + bz
- solve for a. c = 1/2(b + a)
- solve for h. a = πr²h
- solve for z. y = kz/x
- solve for w. r = 2w - t
- solve for a. h = 3a + b²
- solve for c. k = (4ac - b)/2a
Step1: Isolate the variable b in $y = mx + bz$
Subtract $mx$ from both sides.
$y - mx=bz$
Step2: Solve for b
Divide both sides by z (assuming $z
eq0$).
$b=\frac{y - mx}{z}$
Step3: Isolate the variable a in $c=\frac{1}{2}(b + a)$
Multiply both sides by 2.
$2c=b + a$
Step4: Solve for a
Subtract b from both sides.
$a = 2c - b$
Step5: Isolate the variable h in $A=\pi r^{2}h$
Divide both sides by $\pi r^{2}$ (assuming $r
eq0$).
$h=\frac{A}{\pi r^{2}}$
Step6: Isolate the variable z in $y=\frac{kz}{x}$
Multiply both sides by x.
$yx = kz$
Step7: Solve for z
Divide both sides by k (assuming $k
eq0$).
$z=\frac{yx}{k}$
Step8: Isolate the variable w in $r = 2w - t$
Add t to both sides.
$r + t=2w$
Step9: Solve for w
Divide both sides by 2.
$w=\frac{r + t}{2}$
Step10: Isolate the variable a in $h = 3a + b^{2}$
Subtract $b^{2}$ from both sides.
$h - b^{2}=3a$
Step11: Solve for a
Divide both sides by 3.
$a=\frac{h - b^{2}}{3}$
Step12: Isolate the variable c in $k=\frac{4ac - b}{2a}$
Multiply both sides by 2a.
$2ak=4ac - b$
Step13: Move terms involving c to one - side
$2ak + b=4ac$
Step14: Solve for c
Divide both sides by 4a (assuming $a
eq0$).
$c=\frac{2ak + b}{4a}$
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- $b=\frac{y - mx}{z}$
- $a = 2c - b$
- $h=\frac{A}{\pi r^{2}}$
- $z=\frac{yx}{k}$
- $w=\frac{r + t}{2}$
- $a=\frac{h - b^{2}}{3}$
- $c=\frac{2ak + b}{4a}$