Question

solve the inequality.
\\( \frac { 2 } { 7 } > b + \frac { 5 } { 7 } \\)
the solution is \\( \square \\).
graph the solution.

Explanation:

Step1: Subtract \(\frac{5}{7}\) from both sides

$$\frac{2}{7}-\frac{5}{7}>b+\frac{5}{7}-\frac{5}{7}$$

Step2: Simplify the fractions

$$\frac{2 - 5}{7}>b$$
$$-\frac{3}{7}>b$$

Answer:

\(b<-\frac{3}{7}\)

To graph the solution:

• On the number - line, since \(b<-\frac{3}{7}\approx - 0.43\), we use an open circle at \(-\frac{3}{7}\) (because the inequality is strict, \(b\) is not equal to \(-\frac{3}{7}\)) and draw an arrow to the left.