Question

solve for ( x ) and graph the solution on the number line below. if possible, resolve your answer to a single inequality. in case of no solution (( varnothing )), leave the number line blank. ( x + 2 leq -4 ) and ( x + 2 leq -2 ) answer attempt 1 out of 2 inequality notation: number line: -12 -10 -8 -6 -4 -2 0 2 4 6 8 10 12 touch and drag to plot line. submit answer

Explanation:

Step1: Solve first inequality

Solve \( x + 2 \leq -4 \). Subtract 2 from both sides: \( x \leq -4 - 2 \), so \( x \leq -6 \).

Step2: Solve second inequality

Solve \( x + 2 \leq -2 \). Subtract 2 from both sides: \( x \leq -2 - 2 \), so \( x \leq -4 \).

Step3: Find intersection

We need the solution to both inequalities (since it's "and"). The intersection of \( x \leq -6 \) and \( x \leq -4 \) is \( x \leq -6 \) (because all numbers ≤ -6 are also ≤ -4).

Answer:

Inequality Notation: \( x \leq -6 \)
Number Line: On the number line, plot a closed circle at -6 and shade to the left (towards negative infinity).