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solve the following compound inequality. 16y - 18 > 46 or 14y + 6 < 20 …

Question

solve the following compound inequality. 16y - 18 > 46 or 14y + 6 < 20 y > ? or y <

Explanation:

Step1: Solve \(16y - 18 > 46\)

Add 18 to both sides: \(16y - 18 + 18 > 46 + 18\)
Simplify: \(16y > 64\)
Divide both sides by 16: \(\frac{16y}{16} > \frac{64}{16}\)
Simplify: \(y > 4\)

Step2: Solve \(14y + 6 < 20\)

Subtract 6 from both sides: \(14y + 6 - 6 < 20 - 6\)
Simplify: \(14y < 14\)
Divide both sides by 14: \(\frac{14y}{14} < \frac{14}{14}\)
Simplify: \(y < 1\)

Answer:

For \(y > [?]\), the value is \(4\), and for \(y < \), the value is \(1\). So the compound inequality solution is \(y > 4\) OR \(y < 1\).