Question

solve the following compound inequality.
-8 < 3x + 4 ≤ 10
? < x ≤

Explanation:

Step1: Subtract 4 from all parts

Subtract 4 from -8, 3x + 4 and 10.
$-8-4<3x + 4-4\leq10 - 4$
$-12<3x\leq6$

Step2: Divide all parts by 3

Divide -12, 3x and 6 by 3.
$\frac{-12}{3}<\frac{3x}{3}\leq\frac{6}{3}$
$-4 < x\leq2$

Answer:

$-4 < x\leq2$