Question

solve the equation below. what’s the value of g?
\frac{2(15g + 5)}{10} = -5g + 3
\frac{15g + 5}{5} = -5g + 3
3g + 1 = -5g + 3
\underline{+ 5g \qquad \quad + 5g}
\square = \square

Explanation:

Step1: Simplify left side

We have \(\frac{15g + 5}{5}\), divide each term in numerator by 5: \(\frac{15g}{5}+\frac{5}{5}=3g + 1\). So left side is \(3g+1\), right side is \(-5g + 3\).

Step2: Add \(5g\) to both sides

Left side: \(3g+1 + 5g=8g + 1\)
Right side: \(-5g + 3+5g = 3\)

Step3: Solve for \(g\)

Now equation is \(8g+1 = 3\). Subtract 1 from both sides: \(8g=3 - 1=2\). Then divide by 8: \(g=\frac{2}{8}=\frac{1}{4}\) (But for the step where we add \(5g\), the left side after adding \(5g\) to \(3g + 1\) is \(8g+1\) and right side is \(3\))

Answer:

Left box: \(8g + 1\), Right box: \(3\) (and final \(g=\frac{1}{4}\) but for the step shown, left is \(8g + 1\), right is \(3\))