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solve the equation. $3y + 11 = -16$ $y = \\square$

Question

solve the equation.
$3y + 11 = -16$
$y = \square$

Explanation:

Step1: Subtract 11 from both sides

To isolate the term with \( y \), we subtract 11 from both sides of the equation \( 3y + 11 = -16 \). This gives us \( 3y + 11 - 11 = -16 - 11 \), which simplifies to \( 3y = -27 \).

Step2: Divide both sides by 3

To solve for \( y \), we divide both sides of the equation \( 3y = -27 \) by 3. So, \( \frac{3y}{3} = \frac{-27}{3} \), which simplifies to \( y = -9 \).

Answer:

\( y = -9 \)