QUESTION IMAGE
Question
- solve the equation:
16 - 3a = -6a - 5
a. -7
b. -4
c. 4
d. -14
Step1: Add \(6a\) to both sides
To get all the \(a\) terms on one side, we add \(6a\) to both sides of the equation \(16 - 3a=-6a - 5\).
\[16 - 3a+6a=-6a - 5+6a\]
Simplifying both sides, we have \(16 + 3a=-5\).
Step2: Subtract 16 from both sides
Now, we want to isolate the term with \(a\), so we subtract 16 from both sides.
\[16 + 3a-16=-5 - 16\]
Simplifying both sides gives \(3a=-21\).
Step3: Divide by 3
To solve for \(a\), we divide both sides of the equation \(3a = - 21\) by 3.
\[\frac{3a}{3}=\frac{-21}{3}\]
This simplifies to \(a=-7\).
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A. -7