Question

1. solve each equation algebraically. a) $2x^2 + 98 = 0$

Explanation:

Step1: Isolate \(x^2\) term

Subtract 98 from both sides: \(2x^2 = -98\)
Divide both sides by 2: \(x^2 = -49\)

Step2: Solve for \(x\)

Take square root of both sides. Since square of real number can't be negative, we use imaginary unit \(i\) (\(i^2 = -1\)):
\(x = \pm\sqrt{-49} = \pm 7i\)

Answer:

\(x = 7i\) or \(x = -7i\) (where \(i\) is the imaginary unit with \(i^2 = -1\))