solve the absolute value inequality. other than \\( \emptyset \\), use interval notation to express the solution set and graph the solution set on a number line.\\( |x + 4| < 0 \\)\\(\
$$\begin{array}{c}\
\\leftarrow\\hspace{-0.5em}\\begin{array}{ccccccccccccccc}\\\\-10pt\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\
ightarrow\\\\-5pt\\hline\\ -12&-10&-8&-6&-4&-2&0&2&4&6&8&10&12\\\\\\end{array}$$
\
\end{array}\\)\\(\bigcirc\\) bad question, \\( c>0 \\)\\(\bigcirc\\) \\( \emptyset \\)\\(\
$$\begin{array}{c}\
\\leftarrow\\hspace{-0.5em}\\begin{array}{ccccccccccccccc}\\\\-10pt\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\
ightarrow\\\\-5pt\\hline\\ -12&-10&-8&-6&-4&-2&0&2&4&6&8&10&12\\\\\\end{array}$$
\
\end{array}\\)\\(\bigcirc\\) \\( (4, \infty) \\)\\(\
$$\begin{array}{c}\
\\leftarrow\\hspace{-0.5em}\\begin{array}{ccccccccccccccc}\\\\-10pt\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\
ightarrow\\\\-5pt\\hline\\ -12&-10&-8&-6&-4&-2&0&2&4&6&8&10&12\\\\\\end{array}$$
\
\end{array}\\)\\(\bigcirc\\) \\( (-infty, -4) \\)\\(\
$$\begin{array}{c}\
\\leftarrow\\hspace{-0.5em}\\begin{array}{ccccccccccccccc}\\\\-10pt\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\
ightarrow\\\\-5pt\\hline\\ -12&-10&-8&-6&-4&-2&0&2&4&6&8&10&12\\\\\\end{array}$$
\
\end{array}\\)\\(\bigcirc\\) \\( (-4, 4) \\)\\(\
$$\begin{array}{c}\
\\leftarrow\\hspace{-0.5em}\\begin{array}{ccccccccccccccc}\\\\-10pt\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\\bullet&\
ightarrow\\\\-5pt\\hline\\ -12&-10&-8&-6&-4&-2&0&2&4&6&8&10&12\\\\\\end{array}$$
\
\end{array}\\)
