Question

solve for d.

(4 - 3d = d - 8)

(d = ?)

Explanation:

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<reasoning>

Write down the equation

Using the Linear Equations knowledge point
\[
4 - 3d = d - 8
\]

Group variable terms on one side

Using the Linear Equations knowledge point
\[

$$\begin{aligned} 4 - 3d + 3d &= d - 8 + 3d \\ 4 &= 4d - 8 \end{aligned}$$

\]

Isolate the variable term

Using the Linear Equations knowledge point
\[

$$\begin{aligned} 4 + 8 &= 4d - 8 + 8 \\ 12 &= 4d \end{aligned}$$

\]

Solve for d

Using the Linear Equations knowledge point
\[

$$\begin{aligned} \frac{12}{4} &= \frac{4d}{4} \\ 3 &= d \end{aligned}$$

\]
</reasoning>

<answer>
Solve for d.
\(4 - 3d = d - 8\)
d = <blank>3</blank>
</answer>

<post_analysis>
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"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Mathematics",
"Algebra",
"Linear Equations"
]
}
</post_analysis>

Answer:

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<reasoning>

Write down the equation

Using the Linear Equations knowledge point
\[
4 - 3d = d - 8
\]

Group variable terms on one side

Using the Linear Equations knowledge point
\[

$$\begin{aligned} 4 - 3d + 3d &= d - 8 + 3d \\ 4 &= 4d - 8 \end{aligned}$$

\]

Isolate the variable term

Using the Linear Equations knowledge point
\[

$$\begin{aligned} 4 + 8 &= 4d - 8 + 8 \\ 12 &= 4d \end{aligned}$$

\]

Solve for d

Using the Linear Equations knowledge point
\[

$$\begin{aligned} \frac{12}{4} &= \frac{4d}{4} \\ 3 &= d \end{aligned}$$

\]
</reasoning>

<answer>
Solve for d.
\(4 - 3d = d - 8\)
d = <blank>3</blank>
</answer>

<post_analysis>
{
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"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Mathematics",
"Algebra",
"Linear Equations"
]
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