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solve ( x^2 - 36 = 0 ) using square roots. (1 point) ( circ ) ( x = 6 )…

Question

solve ( x^2 - 36 = 0 ) using square roots. (1 point)
( circ ) ( x = 6 ) and ( x = -6 )
( circ ) ( x = 1 ) and ( x = -36 )
( circ ) ( x = 4 ) and ( x = -9 )

Explanation:

Step1: Isolate \(x^2\)

Start with the equation \(x^2 - 36 = 0\). Add 36 to both sides to get \(x^2 = 36\).

Step2: Take square roots

Take the square root of both sides. Remember that \(\sqrt{x^2} = \pm x\), so \(x = \pm\sqrt{36}\). Since \(\sqrt{36} = 6\), we have \(x = 6\) or \(x = -6\).

Answer:

\(x = 6\) and \(x = -6\) (corresponding to the first option among the choices, i.e., the option with \(x = 6\) and \(x = -6\))