solve $(x+4)^2 - 25 = 0$.

$x =$

and

$x =$

Question

solve $(x+4)^2 - 25 = 0$.

$x =$

and

$x =$

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Quadratic Equations", "Solving for Variables" ], "new_concepts": [], "current_concepts": [ "Quadratic Equations", "Solving for Variables", "Difference of Squares" ] } ## Isolate the squared term $$ (x+4)^2 = 25 $$ ## Apply the square root property $$ x+4 = \pm \sqrt{25} $$ $$ x+4 = \pm 5 $$ ## Solve for x $$ \begin{aligned} x_1 &= -4 + 5 = 1 \ x_2 &= -4 - 5 = -9 \end{aligned} $$ $x = 1$ and $x = -9$ { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Quadratic Equations" ] }

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QUESTION IMAGE

Question

Explanation:

Isolate the squared term

Apply the square root property

Solve for x

Answer: