Question

solve.

\\24b^2 + 10b - 21 = 0\\

part 1 of 2

factor the expression on the left side of the equation.

\\\text{box} = 0\\

(type your answer in factored form.)

part 2 of 2

the solution(s) is/are \\(b = \text{box}\\).

(type an integer or a simplified fraction. use a comma to separate answers as needed.)

Explanation:

Factor the quadratic expression

Find two numbers that multiply to \(24 \times (-21) = -504\) and add to \(10\). These numbers are \(28\) and \(-18\).

$$
LATEXBLOCK0
$$

Solve for b

Set each factor to zero to find the solutions.

$$
LATEXBLOCK1
$$

Answer:

Question 1

Factor the expression on the left side of the equation.
<blank>\((4b-3)(6b+7)\)</blank> \( = 0 \)

Question 2

The solution(s) is/are \( b = \) <blank>\(\frac{3}{4}, -\frac{7}{6}\)</blank>.