QUESTION IMAGE
Question
solve for x.
17)
18)
find the measure of angle a.
19)
20)
Step1: Use the triangle - angle - sum theorem
The sum of the interior angles of a triangle is \(180^{\circ}\).
For problem 17:
Step1: Set up the equation
\((x + 70)+76 + 41=180\)
Step2: Simplify the left - hand side
\(x+70+117 = 180\), so \(x + 187=180\)
Step3: Solve for \(x\)
Subtract 187 from both sides: \(x=180 - 187=-7\)
For problem 18:
Step1: Use the right - triangle angle - sum
In a right - triangle (\(90^{\circ}\) angle), \(25+(x + 69)+90=180\)
Step2: Simplify the left - hand side
\(x+25+69 + 90=x + 184\)
Step3: Solve for \(x\)
\(x+184 = 180\), so \(x=180-184=-4\)
For problem 19:
Step1: Apply the triangle - angle - sum theorem
\((57 + x)+(x + 87)+50=180\)
Step2: Combine like terms
\(2x+57+87 + 50=2x+194\)
Step3: Solve for \(x\)
\(2x+194 = 180\), \(2x=180 - 194=-14\), \(x=-7\)
Step4: Find angle \(A\)
Angle \(A=57+x\), substitute \(x = - 7\), \(A=57-7 = 50^{\circ}\)
For problem 20:
Step1: Use the triangle - angle - sum theorem
\((9x + 4)+(16x-4)+80=180\)
Step2: Combine like terms
\(25x+80=180\)
Step3: Solve for \(x\)
\(25x=180 - 80 = 100\), \(x = 4\)
Step4: Find angle \(A\)
Angle \(A=9x + 4\), substitute \(x = 4\), \(A=9\times4+4=40^{\circ}\)
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- \(x=-7\)
- \(x=-4\)
- \(\angle A = 50^{\circ}\)
- \(\angle A = 40^{\circ}\)