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solve for q. -9(q - 10) + 7 < 16

Question

solve for q.
-9(q - 10) + 7 < 16

Explanation:

Step1: Expand the left - hand side

$-9(q - 10)+7=-9q + 90+7=-9q+97$. So the inequality becomes $-9q + 97<16$.

Step2: Subtract 97 from both sides

$-9q+97 - 97<16 - 97$, which simplifies to $-9q<-81$.

Step3: Divide both sides by - 9 and reverse the inequality sign

Since we are dividing by a negative number, the inequality sign flips. So $\frac{-9q}{-9}>\frac{-81}{-9}$, which gives $q > 9$.

Answer:

$q>9$