Question

solutions of potassium iodide (ki) and lead nitrate pb(no₃)₂ are combined, forming lead iodide (pbi₂) and another product. what is the second product, and how many molecules will be produced for each molecule of lead iodide?
oa kno₃; two molecules
ob k₂no₃; one molecule
oc k₂(no₃)₂; one molecule
od k₂(no₃)₂; two molecules

Explanation:

Step1: Write the chemical reaction equation

This is a double - displacement reaction. The general form of a double - displacement reaction is \(AB + CD
ightarrow AD+CB\).
For \(KI\) and \(Pb(NO_3)_2\), the reaction is \(2KI+Pb(NO_3)_2
ightarrow PbI_2 + 2KNO_3\)

Step2: Analyze the stoichiometry

From the balanced chemical equation \(2KI+Pb(NO_3)_2
ightarrow PbI_2 + 2KNO_3\), for each molecule of \(PbI_2\) (\(n = 1\) molecule of \(PbI_2\)), the number of \(KNO_3\) molecules \(n_{KNO_3}\) can be determined by the ratio of their coefficients.
The coefficient of \(PbI_2\) is \(1\) and the coefficient of \(KNO_3\) is \(2\) in the balanced equation.

Answer:

A. \(KNO_3\); two molecules