Question

is (6, 1) a solution to this system of equations?
$y = \frac{1}{3}x - 1$
$y = -\frac{2}{3}x + 3$
options: yes, no

Explanation:

Step1: Substitute into first equation

$y = \frac{1}{3}(6) - 1 = 2 - 1 = 1$ (matches given $y=1$)

Step2: Substitute into second equation

$y = -\frac{2}{3}(6) + 3 = -4 + 3 = -1$ (does not match $y=1$)

Step3: Conclusion

$(6,1)$ fails second equation, so not a solution.

Answer:

no