Question

1. so3 ---------> 2so4 + o2

32+16(3) -> 2(32+16(4)) + 16(2)
144

Explanation:

Step1: Identify the error in the chemical formula

The given reaction has a formula error. The correct reactant for forming sulfate should be \( \ce{SO_3} \) (sulfur trioxide), but the product \( \ce{SO_4} \) is incorrect; it should be \( \ce{SO_2} \) (sulfur dioxide) or the reaction is miswritten. Also, the stoichiometry is wrong. Let's assume we want to balance a correct reaction, say \( 2\ce{SO_3}
ightarrow 2\ce{SO_2} + \ce{O_2} \) (though the original has errors). But focusing on the given (incorrect) reaction's mass calculation:

Left side: \( \ce{SO_3} \) molar mass: \( S = 32 \), \( O = 16 \times 3 = 48 \), so \( 32 + 48 = 80 \). If it's \( 3\ce{SO_3} \) (since left has "32 + 16(3)"? Wait, the writing is unclear. The user wrote "32 + 16(3)" which is \( 32 + 48 = 80 \), but then "144" – maybe 3 moles? \( 3 \times 80 = 240 \), not 144. The right side: \( 2\ce{SO_4} \) – but \( \ce{SO_4} \) is a sulfate ion, not a molecule. \( O_2 \) is 32. This reaction is chemically incorrect (no such reaction as \( \ce{SO_3}
ightarrow 2\ce{SO_4} + \ce{O_2} \)).

Step2: Correct the reaction (hypothetical)

A correct decomposition of sulfur trioxide doesn't occur easily, but if we consider a typo, maybe \( 2\ce{SO_3}
ightarrow 2\ce{SO_2} + \ce{O_2} \). Molar masses: \( \ce{SO_3} = 80 \), \( \ce{SO_2} = 64 \), \( \ce{O_2} = 32 \). For 2 moles of \( \ce{SO_3} \) (160 g), we get 2 moles \( \ce{SO_2} \) (128 g) and 1 mole \( \ce{O_2} \) (32 g), which balances: \( 160 = 128 + 32 \).

But the original problem has a wrong reaction ( \( \ce{SO_3}
ightarrow 2\ce{SO_4} + \ce{O_2} \) is impossible as \( \ce{SO_4} \) has more O than \( \ce{SO_3} \), and S count: left 1 S, right 2 S – unbalanced). So the main issue is the chemical formula error and stoichiometry.

Answer:

The given chemical reaction is incorrect (formula and stoichiometry errors). A correct reaction example: \( 2\ce{SO_3}
ightarrow 2\ce{SO_2} + \ce{O_2} \) (mass balanced: \( 2 \times 80 = 2 \times 64 + 32 \), \( 160 = 128 + 32 \)). The original calculation has errors in formula ( \( \ce{SO_4} \) is not a molecule here) and stoichiometry (S and O counts don't balance).