Question

simplify. express your answer using positive exponents. \\(\frac{k}{k^{-1}}\\)

Explanation:

Step1: Rewrite negative exponent

$k^{-1} = \frac{1}{k}$

Step2: Rewrite division as multiplication

$\frac{k}{k^{-1}} = k \times \frac{k}{1}$

Step3: Multiply terms with exponents

$k \times k = k^{1+1} = k^2$

Answer:

$k^2$