Question

simplify:

\\\frac{2y + 1}{3y + 1} - \frac{1}{3y + 1}\\

(assume all denominators are nonzero)

Explanation:

Combine the fractions over the common denominator

$$ \frac{2y+1}{3y+1} - \frac{1}{3y+1} = \frac{(2y+1) - 1}{3y+1} $$

Simplify the numerator

$$ \frac{2y+1-1}{3y+1} = \frac{2y}{3y+1} $$

Answer:

Simplify:

$$\frac{2y+1}{3y+1}-\frac{1}{3y+1}$$

(Assume all denominators are nonzero)
<blank>\(\frac{2y}{3y+1}\)</blank>