Question

simplify.

\\2y^{-9} w \cdot 9x^3 x^{-3} \cdot 5w^{-6} y^9\\

use only positive exponents in your answer.

Explanation:

Group numerical coefficients and variables

$$ (2 \cdot 9 \cdot 5) \cdot (y^{-9} \cdot y^9) \cdot (w^1 \cdot w^{-6}) \cdot (x^3 \cdot x^{-3}) $$

Apply exponent rules to simplify each group

$$
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$$

Write the final expression with positive exponents

$$ 90 \cdot 1 \cdot w^{-5} \cdot 1 = 90w^{-5} = \frac{90}{w^5} $$

Answer:

\(\frac{90}{w^5}\)