Question

1. a shorted component in an rl series circuit

measures 0 volts across it

causes minimum current

causes current to decrease

measures the applied voltage across it

Explanation:

• For a short - circuited component, by Ohm's law \(V = IR\). When a component is short - circuited, its resistance \(R = 0\). So the voltage across it \(V=I\times0 = 0\) volts.
• When a component in an RL series circuit is shorted, the total resistance of the circuit decreases. According to \(I=\frac{V}{Z}\) (where \(Z=\sqrt{R^{2}+X_{L}^{2}}\) and \(R\) is the total resistance of the non - shorted components), the current in the circuit increases (not decreases or is minimum). And it does not measure the applied voltage (the applied voltage is divided among the non - shorted components).

Answer:

A. measures 0 volts across it