Question

select an orthographic drawing of the figure.
a)
top view
left view
front view
right view
b)
top view
left view
front view
right view

Explanation:

Step1: Analyze Left View

The 3D figure has two layers (front - back) in the left - right direction? Wait, no. Let's look at the left view. The 3D figure, when viewed from the left, should show two squares stacked vertically (since there are two layers in the depth? Wait, no, let's count the blocks. The 3D figure: front column has 3 blocks (vertical), and the right column (front - right) has 1 block, and behind the front column (middle depth) has 2 blocks? Wait, no, looking at the 3D figure: front face has 3 blocks (top, middle, bottom) in the left column, and 1 block in the right column (same height as middle? Wait, no, the 3D figure: let's see the front view of the 3D figure: left column has 3 blocks (vertical), right column has 1 block (same row as middle of left? Wait, no, the 3D figure's front view (as per the diagram) has left column with 3 blocks (top, middle, bottom) and right column with 1 block (at the middle - bottom? Wait, no, the 3D figure is made of blocks: front - left column: 3 blocks (z = 0, y = 0, x = 0; z = 1, y = 0, x = 0; z = 2, y = 0, x = 0), front - right column: 1 block (z = 1, y = 1, x = 0), and behind front - left: two blocks (z = 1, y = 0, x = 1; z = 2, y = 0, x = 1). Now, left view: when looking from the left (x negative direction), we see the layers in y and z. The left view should have two squares vertically (since in the x - direction, the leftmost part has two layers? Wait, no, the left view of the 3D figure: the blocks are arranged such that from the left, we see two squares stacked (because there are two blocks in the depth? Wait, no, the left view of option A has two squares with a red line (indicating a division), and option B has one square. But our 3D figure, when viewed from the left, has two blocks in the depth (x - direction) at the same y and z? Wait, no, the left view: the 3D figure has a column (leftmost) with 3 blocks (z = 0,1,2) and behind it (x = 1) two blocks (z = 1,2). So when viewed from the left (x approaching - infinity), we see the leftmost column (z = 0,1,2) and the column behind (x = 1) at z = 1,2. So the left view should have two squares vertically (since the behind column is at z = 1,2, same as the middle and bottom of the front column). Wait, no, the left view: the height is 2? Wait, no, the left view of option A is a rectangle with two squares (vertically) and a red line, option B is a single square. Our 3D figure, when viewed from the left, has two blocks in the vertical direction? Wait, no, the 3D figure's left side: the front column has 3 blocks (z = 0,1,2), and the column behind (x = 1) has 2 blocks (z = 1,2). So when looking from the left, we see the front column (z = 0,1,2) and the behind column (z = 1,2) overlapping? No, left view is along the y - z plane, x is the depth. So the left view will show the number of blocks in y (left - right) and z (top - bottom) for the maximum x (closest to left). Wait, maybe a better way: count the number of horizontal and vertical divisions. The 3D figure has two layers in the depth (x - direction) for the left - most y - z position. So the left view should have two squares (vertically) as in option A.

Step2: Analyze Top View

Top view: looking from the top (z approaching + infinity), we see the blocks in x (depth) and y (left - right). The front - left (y = 0, x = 0) has a block, front - right (y = 1, x = 0) has a block, and behind front - left (x = 1, y = 0) has two blocks? Wait, no, the top view of option A: three blocks? Wait, no, the top view of option A: the red line is in the middle. Wait, the 3D figure's top view: the top - most blocks are at z = 2 (bottom? No, z = 0 is top? Wait, maybe z is vertical, z = 0 is top, z = 1 is middle, z = 2 is bottom. So top view (z = 0) has front - left (y = 0, x = 0) block, front - right (y = 1, x = 0) block, and behind front - left (x = 1, y = 0) block? No, that's not right. Wait, the 3D figure: front column (y = 0, x = 0) has blocks at z = 0,1,2; front - right (y = 1, x = 0) has block at z = 1; behind front - left (x = 1, y = 0) has blocks at z = 1,2. So top view (z = 0) has only front - left (y = 0, x = 0) block. z = 1: front - left (y = 0, x = 0), front - right (y = 1, x = 0), and behind front - left (x = 1, y = 0). z = 2: front - left (y = 0, x = 0) and behind front - left (x = 1, y = 0). So the top view (combining all z) should have, in the x - y plane, at x = 0 (front), y = 0: 3 blocks (z = 0,1,2), y = 1: 1 block (z = 1); at x = 1 (behind), y = 0: 2 blocks (z = 1,2). So the top view drawing: for option A, the top view has a red line (maybe indicating z = 1), and the blocks: at x = 0, y = 0: two blocks (z = 1,2) and z = 0? Wait, no, the top view in option A: the red line is in the middle of the left - most square, and there are three squares? Wait, option A's top view: left - most column has two squares (vertically with red line), middle square, and right square. Option B's top view: left - most column has three squares? No, option B's top view has left - most column with three squares? Wait, no, the top view of option A: let's count the squares. Option A top view: 3 squares (left column: 2 squares with red line, middle square, right square). Option B top view: left column: 3 squares (top, middle, bottom), middle square, right square. But our 3D figure has at x = 0, y = 0: 3 blocks (z = 0,1,2), x = 0, y = 1: 1 block (z = 1), x = 1, y = 0: 2 blocks (z = 1,2). So the top view (looking from top, z = 0) has x = 0, y = 0: 1 block (z = 0), x = 0, y = 1: 0 blocks (z = 0), x = 1, y = 0: 0 blocks (z = 0). At z = 1: x = 0, y = 0: 1 block, x = 0, y = 1: 1 block, x = 1, y = 0: 1 block. At z = 2: x = 0, y = 0: 1 block, x = 0, y = 1: 0 blocks, x = 1, y = 0: 1 block. So the top view drawing (which shows the projection, so overlapping blocks are shown as connected) should have, for the left - most column (y = 0, x = 0) two blocks (z = 1,2) and z = 0? No, the red line is probably indicating z = 1. So option A's top view has a red line in the middle of the left - most square, meaning two layers (z = 1 and z = 2), and option B's top view has a red line in the middle of the left - most square but with an extra square at the bottom. Wait, no, option A's top view: left column has two squares (with red line), middle square, right square. Option B's top view: left column has three squares (top, middle, bottom with red line in middle), middle square, right square. But our 3D figure has at y = 0, x = 0: 3 blocks (z = 0,1,2), so the top view should show three blocks? No, that's not right. Wait, maybe the red line is a horizontal line, indicating a division between z = 0 - 1 and z = 1 - 2? No, maybe the left view: our 3D figure, when viewed from the left, has two blocks in the vertical direction (since the behind column has two blocks, same as the middle and bottom of the front column). So the left view should have two squares (vertically) as in option A.

Step3: Analyze Front View

The front view of both options A and B are the same? Wait, no, the front view in option A and B: let's check. The front view of the 3D figure should have left column with 3 blocks (vertical) and right column with 1 block. Both options A and B have that.

Step4: Analyze Right View

The right view: looking from the right (y positive direction), we see the blocks in x (depth) and z (top - bottom). The right - most part has a block at z = 1 (y = 1, x = 0, z = 1), and behind it (x = 1, y = 0, z = 1,2). So the right view should have two squares (vertically) with a red line? Wait, option A and B's right view: both have two squares with red lines. Wait, maybe the key is the left view. The 3D figure, when viewed from the left, has two blocks (since there are two layers in the depth for the left - most column). So option A's left view has two blocks (vertically) with a red line, option B's left view has one block. So the correct orthographic drawing is option A.

Answer:

A) (with the top view, left view, front view, right view as in option A)