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Question
select the correct answer.
what is the factored form of \\(x^9 + 27\\)?
\\((x^3 - 3)(x^6 + 3x^3 + 9)\\)
\\((x^3 + 3)(x^6 - 3x^3 + 9)\\)
\\((x - 3)^3(x^6 + 3x^3 + 9)\\)
\\((x + 3)^3(x^6 - 3x^3 + 9)\\)
Rewrite the expression as a sum of cubes
$$
x^9 + 27 = (x^3)^3 + 3^3
$$
Apply the sum of cubes factorization formula
$$
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
$$
$$
LATEXBLOCK0
$$
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- (A) \((x^3 - 3)(x^6 + 3x^3 + 9)\)
- (B) \((x^3 + 3)(x^6 - 3x^3 + 9)\) (Correct answer)
- (C) \((x - 3)(x^6 + 3x^3 + 9)\)
- (D) \((x + 3)(x^6 - 3x^3 + 9)\)