Question

the segment below is dilated by a scale factor of 6 to form \\(\overline{tu}\\). what is the measure of \\(\overline{tu}\\)?

t ----9---- u

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Explanation:

Step1: Recall dilation of a segment

When a segment is dilated by a scale factor \( k \), the length of the new segment is the original length multiplied by \( k \). Here, original length \( TU = 9 \), scale factor \( k = 6 \).

Step2: Calculate \( T'U' \) length

Multiply original length by scale factor: \( T'U' = TU \times 6 = 9 \times 6 = 54 \).

Answer:

54