Question

section 6.1

1. while an object is moving at a constant 20 m/s, a 5 n force pushes the object to the left. at the same time, a 5 n force is pushing the object to the right. what will the objects velocity be after 10 seconds?

Explanation:

Step1: Analyze the net force

The two forces are \(5N\) to the left and \(5N\) to the right. Using the formula for net force \(F_{net}=F_1 + F_2\) (where \(F_1=- 5N\) (left - direction taken as negative) and \(F_2 = 5N\) (right - direction taken as positive)). So, \(F_{net}=-5 + 5=0N\).

Step2: Apply Newton's first law

According to Newton's first law of motion, if \(F_{net} = 0\), then the acceleration \(a=\frac{F_{net}}{m}=0\) (where \(m\) is the mass of the object). The kinematic equation is \(v = v_0+at\). Since \(a = 0\), \(v=v_0\).

Answer:

The object's velocity after \(10\) seconds is \(20m/s\)