Question

section 6.1

1. while an object is moving at a constant 20 m/s, a 5 n force pushes the object to the left. at the same time, a 5 n force is pushing the object to the right. what will the objects velocity be after 10 seconds?

Explanation:

Step1: Analyze the net force

The two forces are equal in magnitude ($5N$) and opposite in direction. So the net force \(F_{net}=5 - 5=0N\).

Step2: Apply Newton's first law

According to Newton's first law of motion, if \(F_{net} = 0\), the acceleration \(a=\frac{F_{net}}{m}=0\) (where \(m\) is the mass of the object). The initial velocity \(u = 20m/s\).
The velocity - time formula is \(v=u+at\). Since \(a = 0\), then \(v=u+0\times t\).

Answer:

The object's velocity after 10 seconds is \(20m/s\).