Question

section 5.2 quantum theory and the atom
in your textbook, read about the bohr model of the atom.
use each of the terms below to complete the statements.
atomic emission spectrum electron frequencies ground state
higher energy levels lower

1. the lowest allowable energy state of an atom is called its
2. bohrs model of the atom predicted the of the lines in hydrogens atomic emission spectrum.
3. according to bohrs atomic model, the smaller an electrons orbit, the the atoms energy level.
4. according to bohrs atomic model, the larger an electrons orbit, the the atoms energy level.
5. bohr proposed that when energy is added to a hydrogen atom, its moves to a higher - energy orbit.
6. according to bohrs atomic model, the hydrogen atom emits a photon corresponding to the difference between the associated with the two orbits it transitions between.
7. bohrs atomic model failed to explain the of elements other than hydrogen.

in your textbook, read about the quantum mechanical model of the atom.
answer the following questions.

1. if you looked closely, could you see the wavelength of a fast - moving car? explain your answer.
2. using de broglies equation, \\(\lambda=\frac{h}{mv}\\) which would have the larger wavelength, a slow - moving proton or a fast - moving golf ball? explain your answer.

Explanation:

1. The ground - state is defined as the lowest - energy state of an atom.
2. Bohr's model predicted the frequencies of lines in hydrogen's atomic emission spectrum.
3. In Bohr's model, smaller electron orbits correspond to lower energy levels.
4. Larger electron orbits mean higher energy levels in Bohr's model.
5. When energy is added to a hydrogen atom, an electron moves to a higher - energy orbit.
6. A hydrogen atom emits a photon corresponding to the energy - level difference between the orbits it transitions between.
7. Bohr's model failed to explain the atomic emission spectra of elements other than hydrogen.
8. The de Broglie wavelength of a fast - moving car is extremely small due to its large mass and is not observable. The de Broglie equation is $\lambda=\frac{h}{mv}$, and for a car, $m$ is large, resulting in a very small $\lambda$.
9. Using $\lambda=\frac{h}{mv}$, a slow - moving proton has a larger wavelength than a fast - moving golf ball. The proton has a much smaller mass than the golf ball, and slower speed also contributes to a larger $\lambda$ according to the formula.

Answer:

1. ground state
2. frequencies
3. lower
4. higher
5. electron
6. energy levels
7. atomic emission spectra
8. No. The de Broglie wavelength of a fast - moving car is extremely small due to its large mass and is not observable.
9. A slow - moving proton. The proton has a much smaller mass than the golf ball, and slower speed also contributes to a larger wavelength according to the de Broglie equation $\lambda=\frac{h}{mv}$.