Question

section 3
ohms law table
9 students have two batteries and two different resistors. during four trials,
they build four different circuits and plan to measure the circuits current in
amps according to the table. for which trial would the students measure the
smallest current in the circuit?
trial 3
trial 2
trial 1
trial 4

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is \(I=\frac{V}{R}\), where \(I\) is current (in amps), \(V\) is voltage (in volts), and \(R\) is resistance (in ohms).

Step2: Calculate current for each trial

• Trial 1: \(I_1=\frac{V_1}{R_1}=\frac{1.5}{200}= 0.0075\space A\)
• Trial 2: \(I_2=\frac{V_2}{R_2}=\frac{1.5}{100}=0.015\space A\)
• Trial 3: \(I_3=\frac{V_3}{R_3}=\frac{3.0}{200}=0.015\space A\)
• Trial 4: \(I_4=\frac{V_4}{R_4}=\frac{3.0}{100}=0.03\space A\)

Since \(0.0075\space A<0.015\space A = 0.015\space A<0.03\space A\), the smallest current is in Trial 1.

Answer:

C. Trial 1