Question

a sealed container can hold 6.28 l co₂ at 1.00 atm and 293 k. how many moles of co₂ fill the container? ? mol co₂ hint: use pv = nrt. amount (mol)

Explanation:

Step1: Identify given values

\(P=1.00\ \text{atm}\), \(V=6.28\ \text{L}\), \(T=293\ \text{K}\), \(R=0.0821\ \frac{\text{L·atm}}{\text{mol·K}}\)

Step2: Rearrange ideal gas law for \(n\)

\(n=\frac{PV}{RT}\)

Step3: Substitute values into formula

\(n=\frac{1.00\times6.28}{0.0821\times293}\)

Step4: Calculate the result

\(n=\frac{6.28}{24.0553}\approx0.261\)

Answer:

0.261 mol CO₂