Question

science 2 t2 lesson 11 homework - thursday 02 july, 2026

1. define what is a parallel circuit
2. define what is a series circuit
3. 1 electron has a very small amount of charge, so we combine a lot of it together to form a bigger unit and this unit is called coulomb, and the symbol for electrical charge is q. 1 c of electrical charge contains \\(6.2 \times 10^{18}\\) of electrons.
4. write down the equation of current and use it to help you define what is current.

\\(i = q \div t\\) current shows us the amount of charge going through a point per second.

1. complete the table

\

$$\begin{tabular}{|l|l|l|} \\hline charge (c) & time (s) & current (a) \\\\ \\hline 1 & 2 & 0.5 \\\\ \\hline 12 & 3 & 4 \\\\ \\hline 6 & 1.2 & 5 \\\\ \\hline 100 & 10 & 10 \\\\ \\hline 30 & 60 & 0.5 \\\\ \\hline 100 & 50 & 2 \\\\ \\hline 20 & 5 & 4 \\\\ \\hline 180 & 120 & 1.5 \\\\ \\hline 60 & 20 & 3 \\\\ \\hline \\end{tabular}$$

1. the unit for current is ampere or coulomb per second.
2. in a series circuit current \underline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad}; in a parallel circuit current \underline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad}.
3. the current going through a lamp is 5a. use the definition of current to explain what does this mean?

5a = 5c/s. current shows us the amount of charge going through a point per sec. this means 5 coulombs of charge (\\(5 \times 6.2 \times 10^{18} = 3.1 \times 10^{19}\\)) electrons will go through every second.

1. if the current coming out a battery is 2 a, calculate how much charge will come out of the battery in 1 hour.

\\(i = 2\text{ a}\\), \\(t = 1\text{ h}\\)
\\(t = 1 \times 3600\text{ s}\\)
\\(2 \times 3600 = 7200\text{ c}\\)

1. describe what is a short circuit and why it is dangerous.
2. the current in the battery is 4 a. the two light bulbs are identical. calculate a1 a2 a3 and a4.

Explanation:

Step1: Define parallel circuit

A parallel circuit has multiple paths for current.

Step2: Define series circuit

A series circuit has a single path for current.

Step3: Fill in blanks for charge unit

Charge unit is Coulomb (\(Q\)), containing \(6.24 \times 10^{18}\) electrons.

Step4: Write current equation and definition

\(I = \frac{Q}{t}\); current is charge flow rate.

Step5: Calculate missing values in table

Use \(Q = I \times t\), \(I = \frac{Q}{t}\), and \(t = \frac{Q}{I}\).

Step6: Identify current units

Current units are Ampere or coulomb per second.

Step7: Describe current behavior

Series current is constant; parallel current splits.

Step8: Explain 5A current meaning

\(5\text{ A}\) means \(5\text{ C}\) of charge passes per second.

Step9: Calculate charge in 1 hour

$$Q = I \times t = 2\text{ A} \times 3600\text{ s} = 7200\text{ C}$$

Step10: Define short circuit danger

Low-resistance path causes high current and fire hazards.

Step11: Calculate currents in circuit

Total current splits equally between two identical parallel branches.

Answer:

1. A parallel circuit is an electrical circuit with multiple paths for current to flow, where components are connected across the same common points.
2. A series circuit is an electrical circuit with only one path for current to flow, where components are connected end-to-end in a single loop.
3. Coulomb; \(Q\); \(6.24 \times 10^{18}\)
4. \(I = \frac{Q}{t}\); Current is the rate of flow of electric charge past a point in a circuit.
5. See the completed table below:

Charge (C)	Time (s)	Current (A)
12	3	4
6	1.2	5
100	10	10
30	60	0.5
100	50	2
20	5	4
180	120	1.5
60	20	3

1. Ampere; coulomb per second
2. is the same at all points; splits along the parallel branches
3. A current of \(5\text{ A}\) means that \(5\text{ coulombs}\) of electrical charge pass through a point in the lamp every second.
4. \(7200\text{ C}\)
5. A short circuit is an unintended low-resistance path that bypasses the main load in a circuit. It is dangerous because it causes an excessively high current to flow, which can lead to overheating, melting wires, or electrical fires.
6. \(\text{A}_1 = 4\text{ A}\), \(\text{A}_2 = 2\text{ A}\), \(\text{A}_3 = 2\text{ A}\), \(\text{A}_4 = 4\text{ A}\)