Question

a sample of a gas has a pressure of 1.01 atm when the volume is 256 ml. what is the pressure of the gas when the volume is 118 ml?
select the correct answer below:
2.08 atm
1.83 atm
0.466 atm
2.19 atm

Explanation:

Step1: Apply Boyle's Law

Boyle's Law is \(P_1V_1 = P_2V_2\). Here, \(P_1 = 1.01\) atm, \(V_1=256\) mL, \(V_2 = 118\) mL. We need to find \(P_2\).

Step2: Rearrange the formula for \(P_2\)

From \(P_1V_1 = P_2V_2\), we get \(P_2=\frac{P_1V_1}{V_2}\).

Step3: Substitute the values

Substitute \(P_1 = 1.01\) atm, \(V_1 = 256\) mL, \(V_2=118\) mL into the formula: \(P_2=\frac{1.01\times256}{118}\).

Step4: Calculate \(P_2\)

\(1.01\times256 = 258.56\), then \(\frac{258.56}{118}\approx2.08\) atm.

Answer:

A. 2.08 atm