Question

a sample of h₂so₄ is found to contain 1.05 g of h, 16.67 g of s, and 33.28 g of o. what is the percent composition of o in the compound? ?% o

Explanation:

Step1: Calculate the total mass of the compound

The total mass of the compound is the sum of the masses of \(H\), \(S\), and \(O\).

$$m_{total}=1.05 + 16.67+33.28$$

$$m_{total}=51\space g$$

Step2: Calculate the percent composition of \(O\)

The formula for percent composition is \(\text{Percent Composition}=\frac{\text{Mass of Component}}{\text{Total Mass of Compound}}\times100\%\)
For \(O\), \(\text{Mass of Component} = 33.28\space g\) and \(\text{Total Mass of Compound}=51\space g\)

$$ \text{Percent Composition of }O=\frac{33.28}{51}\times 100\%$$

$$ \text{Percent Composition of }O = 65.25\%$$

Answer:

\(65.25\%\)