Question

a sample of carbon dioxide occupies a volume of 3.50 l at 125 kpa pressure. what pressure would the gas exert if the volume was decreased to 2.00 l? use the formula: $p_1v_1 = p_2v_2$ 2.19 kpa 18.8 kpa 21.9 kpa 219 kpa done

Explanation:

Step1: Identify known values

We know \( P_1 = 125 \, \text{kPa} \), \( V_1 = 3.50 \, \text{L} \), and \( V_2 = 2.00 \, \text{L} \). We need to find \( P_2 \) using the formula \( P_1V_1 = P_2V_2 \).

Step2: Rearrange the formula to solve for \( P_2 \)

From \( P_1V_1 = P_2V_2 \), we can solve for \( P_2 \) by dividing both sides by \( V_2 \):
\( P_2 = \frac{P_1V_1}{V_2} \)

Step3: Substitute the known values into the formula

Substitute \( P_1 = 125 \, \text{kPa} \), \( V_1 = 3.50 \, \text{L} \), and \( V_2 = 2.00 \, \text{L} \) into the formula:
\( P_2 = \frac{(125 \, \text{kPa})(3.50 \, \text{L})}{2.00 \, \text{L}} \)

Step4: Calculate the result

First, multiply \( 125 \) and \( 3.50 \): \( 125 \times 3.50 = 437.5 \). Then divide by \( 2.00 \): \( \frac{437.5}{2.00} = 218.75 \, \text{kPa} \), which rounds to \( 219 \, \text{kPa} \).

Answer:

219 kPa