Question

the sabatier reaction is used on space missions to remove carbon dioxide exhaled by the astronauts. it also produces clean drinking water and methane that can be used for fuel.
astronaut working on the space station
the chemical equation for this reaction is shown below.
co₂(g) + 4h₂(g) → 2h₂o(l) + ch₄(g)
use the chemical equation to complete the statements.
· carbon dioxide (co₂) has a of 2.
· hydrogen (h₂) has a of 4.
· methane (ch₄) has a of 4.
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Explanation:

Step1: Analyze the chemical equation

In the chemical equation \(CO_{2}(g)+4H_{2}(g)\to2H_{2}O(l)+CH_{4}(g)\), the coefficients are the numbers in front of the chemical formulas.

Step2: Identify the coefficient for \(CO_{2}\)

For \(CO_{2}\), there is no number written in front of it. In chemical equations, when no number is present, the coefficient is \(1\). But looking at the structure of the question (the blanks are likely for coefficients as per the stoichiometry of the reaction), wait, no - wait the question is about what property has a value. Wait, in a chemical equation, the numbers in front of the formulas are called coefficients. For \(CO_{2}\), since there is no number, but in the context of the reaction \(CO_{2}(g)+4H_{2}(g)\to2H_{2}O(l)+CH_{4}(g)\), the coefficient of \(CO_{2}\) is \(1\), but wait no - wait the problem is miswritten? No, wait the first blank: Carbon dioxide \((CO_{2})\) has a [blank] of \(2\). Wait no - wait looking at the reaction \(CO_{2}(g)+4H_{2}(g)\to2H_{2}O(l)+CH_{4}(g)\). The sub - script of \(O\) in \(CO_{2}\) is \(2\). The coefficient of \(H_{2}\) is \(4\). The sub - script of \(H\) in \(CH_{4}\) is \(4\).

Answer:

• Carbon dioxide \((CO_{2})\) has a sub - script of \(2\).
• Hydrogen \((H_{2})\) has a coefficient of \(4\).
• Methane \((CH_{4})\) has a sub - script of \(4\).