QUESTION IMAGE
Question
a rotation by angle \\( \angle a c e \\) using point \\( c \\) as the center takes triangle \\( c b a \\) onto triangle \\( c d e \\).
a. explain why the image of ray \\( c a \\) lines up with ray \\( c e \\).
b. explain why the image of \\( a \\) coincides with \\( e \\).
c. is triangle \\( c b a \\) congruent to triangle \\( c d e \\)?
yes. no.
explain your reasoning
Step1: Rotation property
A rotation is a transformation that preserves the length of segments and the measure of angles. When we rotate around point \(C\) by angle \(∠ACE\), the ray \(CA\) is rotated to \(CE\) because the rotation is centered at \(C\) and the angle of rotation is \(∠ACE\). So, the image of ray \(CA\) lines up with ray \(CE\) due to the definition of rotation (a rotation about a point \(C\) moves a point \(A\) along a circular arc centered at \(C\) and the angle of rotation determines the new position of the ray starting at \(C\)).
Step2: Rotation of point \(A\)
Since \(CA = CE\) (radii of the same circle of rotation, because in a rotation about \(C\), the distance from \(C\) to any point and its image is the same). When we rotate \(\triangle CBA\) about \(C\) by \(∠ACE\), point \(A\) (which is at a distance \(CA\) from \(C\)) is moved along the circular path centered at \(C\) with radius \(CA\) to point \(E\) (since \(CE=CA\) and the angle of rotation is \(∠ACE\)).
Step3: Congruence of triangles
Rotation is a rigid - motion transformation. Rigid - motion transformations (translations, rotations, reflections) preserve the shape and size of a figure. So, if \(\triangle CBA\) is rotated to \(\triangle CDE\), then \(\triangle CBA\cong\triangle CDE\) because rotation is a congruence transformation. All corresponding sides (\(CB = CD\), \(CA=CE\), \(BA = DE\)) and corresponding angles (\(∠CBA=∠CDE\), \(∠BCA = ∠DCE\), \(∠CAB=∠CED\)) are equal.
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
a. Because a rotation about point \(C\) by \(∠ACE\) moves ray \(CA\) to ray \(CE\) (rotation property).
b. Since \(CA = CE\) (radii of rotation) and the rotation about \(C\) by \(∠ACE\) moves \(A\) to \(E\).
c. Yes. Rotation is a rigid - motion (congruence transformation) that preserves side lengths and angle measures.