Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

1.) rotating in the positive direction, label each common angle in radi…

Question

1.) rotating in the positive direction, label each common angle in radians on the circle below. begin with 0 and end with 2π.
2.) rotating in the negative direction, label the common angles in radians. include every angle from -2π to 0.

Explanation:

Step1: Recall the relationship between positive and negative angles

Angles in the negative direction are equivalent to \(2\pi\) minus the corresponding positive - angle. For example, if we have a positive angle \(\theta\), the negative - equivalent angle \(\alpha=-\theta + 2k\pi\) (in the range \(-2\pi\leqslant\alpha\leqslant0\), \(k = 0\) or \(k = 1\)).

Step2: List the common angles

The common angles (in positive direction) we usually consider are \(0,\frac{\pi}{6},\frac{\pi}{4},\frac{\pi}{3},\frac{\pi}{2},\frac{2\pi}{3},\frac{3\pi}{4},\frac{5\pi}{6},\pi,\frac{7\pi}{6},\frac{5\pi}{4},\frac{4\pi}{3},\frac{3\pi}{2},\frac{5\pi}{3},\frac{7\pi}{4},\frac{11\pi}{6},2\pi\).
For \(\theta=\frac{\pi}{6}\), the negative - equivalent angle \(\alpha=- \frac{11\pi}{6}\) (since \(-\frac{\pi}{6}+2\pi=\frac{11\pi}{6}\) is positive, \(-\frac{\pi}{6}\) is not in the range \(-2\pi\leqslant\alpha\leqslant0\), and \(-\frac{\pi}{6}- 2\pi=-\frac{13\pi}{6}\) is not a common angle. Using \(\alpha = 2\pi-\frac{\pi}{6}-2\pi=-\frac{11\pi}{6}\)).
For \(\theta=\frac{\pi}{4}\), \(\alpha=-\frac{7\pi}{4}\) (because \(2\pi-\frac{\pi}{4}-2\pi =-\frac{7\pi}{4}\)).
For \(\theta=\frac{\pi}{3}\), \(\alpha=-\frac{5\pi}{3}\) (since \(2\pi-\frac{\pi}{3}-2\pi=-\frac{5\pi}{3}\)).
For \(\theta=\frac{\pi}{2}\), \(\alpha=-\frac{3\pi}{2}\) (because \(2\pi-\frac{\pi}{2}-2\pi=-\frac{3\pi}{2}\)).
For \(\theta=\frac{2\pi}{3}\), \(\alpha=-\frac{4\pi}{3}\) (since \(2\pi-\frac{2\pi}{3}-2\pi=-\frac{4\pi}{3}\)).
For \(\theta=\frac{3\pi}{4}\), \(\alpha=-\frac{5\pi}{4}\) (because \(2\pi-\frac{3\pi}{4}-2\pi=-\frac{5\pi}{4}\)).
For \(\theta=\frac{5\pi}{6}\), \(\alpha=-\frac{7\pi}{6}\) (since \(2\pi-\frac{5\pi}{6}-2\pi=-\frac{7\pi}{6}\)).
For \(\theta=\pi\), \(\alpha=-\pi\).

Answer:

Starting from the positive \(x -\)axis (going clock - wise): \(0,-\frac{\pi}{6},-\frac{\pi}{4},-\frac{\pi}{3},-\frac{\pi}{2},-\frac{2\pi}{3},-\frac{3\pi}{4},-\frac{5\pi}{6},-\pi,-\frac{7\pi}{6},-\frac{5\pi}{4},-\frac{4\pi}{3},-\frac{3\pi}{2},-\frac{5\pi}{3},-\frac{7\pi}{4},-\frac{11\pi}{6},- 2\pi\)