Question

rewrite without parentheses and simplify.
$(3v + 8u)^2$

Explanation:

Step1: Recall the square of a binomial formula

The formula for \((a + b)^2\) is \(a^2 + 2ab + b^2\). Here, \(a = 3v\) and \(b = 8u\).

Step2: Calculate \(a^2\)

\(a^2=(3v)^2 = 9v^2\)

Step3: Calculate \(2ab\)

\(2ab = 2\times(3v)\times(8u)=48uv\)

Step4: Calculate \(b^2\)

\(b^2=(8u)^2 = 64u^2\)

Step5: Combine the terms

\((3v + 8u)^2=9v^2+48uv + 64u^2\)

Answer:

\(9v^2 + 48uv + 64u^2\)