QUESTION IMAGE
Question
rewrite the following without an exponent.
\\(\frac{1}{8^{-2}}\\)
Step1: Apply negative exponent rule
A negative exponent in the denominator can be moved to the numerator and made positive: $\frac{1}{a^{-n}} = a^n$. For this problem, $a=8$, $n=2$, so:
$\frac{1}{8^{-2}} = 8^2$
Step2: Evaluate the positive exponent
Calculate $8$ multiplied by itself:
$8^2 = 8 \times 8$
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$64$